E5D Phase angle between voltage and
current; impedances and phase
angles of series and parallel circuits; algebraic operations using
complex numbers: rectangular coordinates (real and imaginary parts);
polar
coordinates (magnitude and angle)
E5D01
(A)
What is
the phase angle between the voltage across and the current through a series
R-L-C circuit if XC is 25 ohms, R is 100 ohms, and XL is 100 ohms?
A. 36.9 degrees with the
voltage leading the current
B. 53.1 degrees with the voltage lagging the
current
C. 36.9 degrees with the voltage lagging the
current
D. 53.1 degrees with the voltage leading the
current
E5D02
(C)
What is
the phase angle between the voltage across and the current through a series
R-L-C circuit if XC is 500 ohms, R is 1 kilohm, and XL is 250 ohms?
A. 68.2 degrees with the voltage leading the
current
B. 14.1 degrees with the voltage leading the
current
C. 14.1 degrees with the
voltage lagging the current
D. 68.2 degrees with the voltage lagging the
current
E5D03 (D)
What is
the phase angle between the voltage across and the current through a series
R-L-C circuit if XC is 50 ohms, R is 100 ohms, and XL is 25 ohms?
A. 76 degrees with the voltage lagging the
current
B. 14 degrees with the voltage leading the
current
C. 76 degrees with the voltage leading the
current
D. 14 degrees with the
voltage lagging the current
E5D04
(A)
What is
the phase angle between the voltage across and the current through a series
R-L-C circuit if XC is 100 ohms, R is 100 ohms, and XL is 75 ohms?
A. 14 degrees with the
voltage lagging the current
B. 14 degrees with the voltage leading the
current
C. 76 degrees with the voltage leading the
current
D. 76 degrees with the voltage lagging the
current
E5D05
(D)
What is
the phase angle between the voltage across and the current through a series
R-L-C circuit if XC is 50 ohms, R is 100 ohms, and XL is 75 ohms?
A. 76 degrees with the voltage leading the
current
B. 76 degrees with the voltage lagging the
current
C. 14 degrees with the voltage lagging the
current
D. 14 degrees with the
voltage leading the current
E5D06
(D)
What is
the relationship between the current through and the voltage across a
capacitor?
A. Voltage and current are in phase
B. Voltage and current are 180 degrees out of
phase
C. Voltage leads current by 90 degrees
D. Current leads voltage by
90 degrees
E5D07
(A)
What is
the relationship between the current through an inductor and the voltage across
an inductor?
A. Voltage leads current by
90 degrees
B. Current leads voltage by 90 degrees
C. Voltage and current are 180 degrees out of
phase
D. Voltage and current are in phase
E5D08
(B)
In
polar coordinates, what is the impedance of a network comprised of a
100-ohm-reactance inductor in series with a 100-ohm resistor?
A. 121 ohms, /__35_degrees__
B. 141 ohms, /__45_degrees__
C. 161 ohms, /__55_degrees__
D. 181 ohms, /__65_degrees__
E5D09
(D)
In
polar coordinates, what is the impedance of a network comprised of a
100-ohm-reactance inductor, a 100-ohm-reactance capacitor, and a 100-ohm
resistor all connected in series?
A. 100 ohms, /__90_degrees__
B. 10 ohms, /__0_degrees__
C. 10 ohms, /__100_degrees__
D. 100 ohms, /__0_degrees__
E5D10
(A)
In
polar coordinates, what is the impedance of a network comprised of a
300-ohm-reactance capacitor, a 600-ohm-reactance inductor, and a 400-ohm
resistor, all connected in series?
A. 500 ohms, /__37_degrees__
B. 400 ohms, /__27_degrees__
C. 300 ohms, /__17_degrees__
D. 200 ohms, /__10_degrees__
E5D11
(B)
In rectangular
coordinates, what is the impedance of a network comprised of a 1.0-millihenry
inductor in series with a 200-ohm resistor at 30 kHz?
A. 200 - j188
B. 200 + j188
C. 188 - j200
D. 188 + j200
E5D12
(C)
In
rectangular coordinates, what is the impedance of a network comprised of a
10-millihenry inductor in series with a 600-ohm resistor at 10 kHz?
A. 628 + j600
B. 628 - j600
C. 600 + j628
D. 600 - j628
E5D13
(B)
In
rectangular coordinates, what is the impedance of a network comprised of a 0.1-microfarad
capacitor in series with a 40-ohm resistor at 50 kHz?
A. 40 + j32
B. 40 - j32
C. 32 - j40
D. 32 + j40