From: Thomas Jackson ([email protected])
Date: Thu Feb 15 2001 - 12:59:42 PST
Keith,
The velocity of propagation through a dielectric media, V, is related to the
free speed of light, C, as follows:
C = V x sqrt(Er)
Where Er is the relative dielectric constant. So since the speed of light
in a vacuum, C, is constant, increasing Er decreases V, the velocity of
propagation through the media. The lowest possible Er is 1.0 for an
absolute vacuum. Air has an Er of about 1.0008.
Tom
Thomas L. Jackson, P.E.
Staff VLSI Design Engineer
Network Access Development
Systems Solutions Group
FUJITSU MICROELECTRONICS, INC.
3545 North First Street
San Jose, CA 95134-1804
telephone: (408) 922-9574
facsimile: (408) 922-9618
http://www.fujitsumicro.com
-----Original Message-----
From: Kowal, Keith [mailto:[email protected]]
Sent: Thursday, February 15, 2001 12:19 PM
To: '[email protected]'
Subject: [SI-LIST] : Simple question about propagation speed vs. dielectric
Folks,
IN general , is it true or false, signals travel faster the lower the Er
,, or not //// why or whynot?
keith
Digital Networks, LLC
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