**From:** Ray Anderson (*[email protected]*)

**Date:** Thu Aug 31 2000 - 11:12:17 PDT

**Next message:**Ingraham, Andrew: "RE: [SI-LIST] : skin effect"**Previous message:**Barry Ma: "Re: [SI-LIST] : skin effect"**Maybe in reply to:**C Deibele: "[SI-LIST] : skin effect"**Next in thread:**Ingraham, Andrew: "RE: [SI-LIST] : skin effect"

.Can I ask you a favour? It would be something you really don't want to do

*>this morning i.e. can you let me know
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*>the equation which would let you figure out the skin depth at various
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*>frequencies. I would really appreciate it.
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*>
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*>I guess I had wrong numbers in mind when I was talking to my boss....
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*>
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*>cheers,
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*>
*

*>Muhammad
*

OK, here you go:

From Pozar's "Microwave Engineering" page 27 I paraphrase:

skin depth = sqrt(2/(omega * mu * sigma))

= sqrt(1/(pi * freq * mu0 * sigma))

= sqrt(1/(pi * freq * 4pi * 10^-7)) * sqrt(1/sigma)

so for freq = 10 GHz , sqrt(1/(pi * 10^10 * 4pi * 10^-7)) = 5.03 x 10^-3

therefore at 10 GHz skin effect = (5.03 x 10^-3) * sqrt(1/sigma)

for copper sigma = 5.813 x 10^7 skin depth @ 10 GHz = 6.60 x 10^-7 m

aluminum sigma = 3.816 x 10^7 skin depth @ 10 GHz = 8.14 x 10^-7 m

silver sigma = 6.173 x 10^7 skin depth @ 10 GHz = 6.40 x 10^-7 m

-Ray

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