From: Bob Lewandowski ([email protected])
Date: Wed Mar 08 2000 - 18:07:04 PST
From the March 1967 printing of "Reference Data for Radio Engineerss" published by IT&T:
For a single wire, near ground: (parallel to ground, where d = wire diameter, and h = height of wire above ground)
For d << h,
Z0=(138/(SQRT(Epislon R))) *LOG10(4*h/d)
opams cybernetics wrote:
> Hi SI-gurus,
> One stupid question:
> Take a long (say 10 ft) long rod of perfect conductor (say copper) and
> connect one of its end to the +ve terminal of a battery through a
> switch. The other end of the battery is grounded to the earth.
> Now this rod should behave as a transmission line when you quickly close
> the swich, right? How do you calculate the impedance of this line? Does
> this mean that the impedance will be different when you put the rod
> parallel the the earth and when put perpendicular to the earth (because
> the distance from the earth and hence capacitance to the ground is
> Sorry for this silly question.
> **** To unsubscribe from si-list or si-list-digest: send e-mail to [email protected] In the BODY of message put: UNSUBSCRIBE si-list or UNSUBSCRIBE si-list-digest, for more help, put HELP.
> si-list archives are accessible at http://www.qsl.net/wb6tpu
**** To unsubscribe from si-list or si-list-digest: send e-mail to [email protected] In the BODY of message put: UNSUBSCRIBE si-list or UNSUBSCRIBE si-list-digest, for more help, put HELP.
si-list archives are accessible at http://www.qsl.net/wb6tpu
This archive was generated by hypermail 2b29 : Thu Apr 20 2000 - 11:35:30 PDT