From: Eric Bogatin ([email protected])
Date: Wed Dec 15 1999 - 15:12:06 PST
You probably don't want the mutual inductance between the planes. You might
want the loop inductance between two planes, or the effective inductance of
one plane when the other is the return path. The formula you mentioned is
close to the loop inductance- what you have is actually 1/2 the loop
inductance, which is the effective or net inductance of one plane.
When you do the unit conversion, you get L_loop = 33pH/sq per mil x h
h is the dielectric thickness in mils, between the two planes
33 pH/sq is the loop inductance of two planes that are separated by 1 mil.
If you take two planes 1 cm on a side, and short one edge, the loop
inductance measured between the two planes at the other end will be 33 pH.
If you double the width, you will half the loop inductance. If you double
the length you will double the loop inductance. So, any square shaped
structure will have the same loop inductance, for the same plane to plane
spacing. If it's not a square, calc the number of squares, as L/w, and
multiply by the loop inductance per square.
In your example, the loop inductance is about 33 pH/sq/mil x (12 mm) ~
33pH/sq/mil x 500 mil = 16nH.
This approximation is based on the parallel plate approximation, which is
good to better than 10% so long as the width is > 20x the thickness. I have
compared this approximation to a 3D field solver and I get agreement to
better than 2% for 100:1 aspect ratios. In your case, the aspect ratio is
about 5:1, so the approximation is probably good to maybe 30%. A 1/2 inch
thickness between power and ground planes is a bit large. Are you sure it is
Inductance is one of the topics we review in my Fundamental Principles of SI
class, which you can check out on our web site. Good luck.
Training for Signal Integrity and Interconnect Design
26235 W. 110th Terr.
Olathe, KS 66061
e: [email protected]
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]]On Behalf Of Chang, Isaac Yew
> Sent: Tuesday, December 14, 1999 7:34 PM
> To: [email protected]
> Subject: [SI-LIST] : Mutual Inductance between 2 Power Planes
> Importance: High
> I have a question here on how to calculate the mutual
> inductance(M) between
> 2 power planes that have the similar dimensions(L=63mm, W=50mm,
> with a separation of d=12mm. I have tried using Grivet(conf. mapping)
> formula (ie. M = uLd/(2w) ) to calculate and found out the M is
> too big. Can
> anyone comment and help?
> Isaac Chang
> Intel Technology Sdn. Bhd.
> Test Hardware Development Engineer
> Tel : 604-859-5738
> Fax : 604-859-5730
> Email : [email protected]
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