On calculating the strength of current in amperes if a charge of 840C (coulomb) passes through an electrolyte in 7 minutes, it will be

- 1
- 2
- 3
- 4

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#### Solution

type 1

A = C/s

∴ A = 840/(7 × 60)

∴ A = 840/420

∴ A = 2

type 2

2

Q =I × t

840= I × 420

I =2 A

Concept: Electrolytic Cells and Electrolysis - Introduction

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