1:   Zl   = 450 - 240j (Z0 = 300 Ohm, 
                       Vf = 0.98,
                       F  = 50 MHz)
2:   Zln  = 1.5 - 0.8j (@ 0.306 lambda)
3:   L�nea de transmisi�n
4:   Z1n  = 1.0 - 0.78j (@ 0.346 lambda)
5:   Xlsn =     + 0.78j
6:   Zgn  = 1

7:   L�nea = 0.346 - 0.306 
           = 0.04 lambda
           = Vf * 300/F * 0.04
           = 235mm
9:   Zlsn -> Zls = 234 jOhm
         -> 745nH