// IntAverage - average three numbers using integer
//              data type
#include <stdio.h>
#include <iostream.h>

int main(int nArg, char* pszArgs[])
{
    int nValue1;
    int nValue2;
    int nValue3;

    cout << "Integer version\n";
    cout << "Input three numbers (follow each with newline)\n";
    cout << "#1:";
    cin  >> nValue1;

    cout << "#2:";
    cin  >> nValue2;

    cout << "#3:";
    cin  >> nValue3;

    // the following solution suffers from minor roundoff
    cout << "The add before divide average is:";
    cout << (nValue1 + nValue2 + nValue3)/3;
    cout << "\n";

    // this version suffers from serious roundoff
    cout << "The divide before add average is:";
    cout << nValue1/3 + nValue2/3 + nValue3/3;
    cout << "\n";

    cout << "\n\n";
    return 0;
 }