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Ohm's Law
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If a 4800 ohm resistor is connected to a 12 volt battery, the current flow is:
a.
2.5 mA
b. 25 mA
c. 40 A
d. 400 A
Your answer "a" is CORRECT!
I = E / R
= 12 / 4800
= 0.0025 Amps, which is 2.5 mA
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