From: JNH (John@quantatw.com)
Date: Tue Sep 19 2000 - 05:16:26 PDT
It is very good of your explanation. However, I have one question. Look at
the profile of a via, we know that
a via is a cylinder physical structure. I cannot see the second cylinder
wrapped the first one, connected to ground.
The Capacitance of via seems to be formed by the first cylinder and the
cross section of plane of ground.
D2-D1 is the clearance hole between the cylinder and the plane.
SI Specialist, ARD4
Quanta Computer Inc.,Taiwan, R.O.C.
Tel: 886+3+3979000 ext. 5183
From: Pierre-Luc Cantin [mailto:firstname.lastname@example.org]
Sent: Sunday, September 17, 2000 7:43 AM
To: 'email@example.com'; 'firstname.lastname@example.org'
Subject: RE: [SI-LIST] : parasitic value for via
With the help of Ozgur, thank you Ozgur for your contribution,
here the revised demonstration of Johnson via capacitance
- picture the via being a cylinder diameter=D1
- picture a second cylinder wrapped around the first one D2>D1
- this second one represents power/gnd planes
- both cylinders are iso-potential
- un-fold both cylinders and you end up with two parallel plates.
- the separation between the plates is the via clearance (D2-D1)/2
- the height of both cylinders is the board thickness (T)
- the width of the unfold-cylinder is equal to the via circumference which
is it's diameter times pi=3.1416... (pi*D1).
Now let do the math using Johnson example as a reference:
- T=63mil ---> 1600um
- D1=28mil ---> 711um
- D2=50mil ---> 1270um
....Cvia = 1.41*4.7*0.063*0.028/(0.050-0.028) = 0.53pF
Now using two parallel plates capacitance formula:
Cvia= er*eo*A/d = er*eo*T*D1*pi/(D2-D1)/2, eo=8.85aF/um
= 531589aF = 0.531pF !!!
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