From: Zabinski, Patrick J. ([email protected])
Date: Mon Aug 21 2000 - 05:20:59 PDT
See comments inserted below:
> Can you explain little bit more on power consumption of PECL
> & CML with
> equations? Which is better?
Oops; another brain-cramp.
In ECL, the total power dissipation would be:
P = V^2 / R
= 80 mW
That's per single ended signal. For a diff pair,
power would be 2 * 80 = 160 mW.
For CML, the total voltage drop is VCC-VEE, and the
current is dictated by the technology you happen to
be using, which generally ranges from 3 to 8 mA. So,
power would be:
P = V * I
= (VCC-VEE) * IEE
= 5 * 0.008 (worst case; most often better)
= 40 mW
Because common CML implementations force the current
(8 mA) through either the true or complement, there is no
need to double the power dissipation.
So, P(ECL) = 80 mW
P(CML) = 40 mW
i.e., P(ECL) >= 2 * P(CML)
(did I get it right this time?)
> It will be better if you give any information on CML(like app notes..)
I don't know of any app notes, but here are two references
for additional reading on CML:
TITLE DC Analysis of Current Mode Logic
AUTHOR Ronald L. Treadway
SOURCE IEEE Circuits and Devices Magazine
DATE March, 1989
TITLE High-Speed InP HBT Circuits, Chapter 8
AUTHOR J. F. Jensen, L. M. Burns, and W. E. Stanchina
(I got a preliminary copy of this chapter before
publication, and I never did find out who published
it, copyright date, ISBN, etc. However, if
you work with CML, this chapter is pretty useful.
**** To unsubscribe from si-list or si-list-digest: send e-mail to
[email protected] In the BODY of message put: UNSUBSCRIBE
si-list or UNSUBSCRIBE si-list-digest, for more help, put HELP.
si-list archives are accessible at http://www.qsl.net/wb6tpu
This archive was generated by hypermail 2b29 : Tue May 08 2001 - 14:29:18 PDT