RE: [SI-LIST] : HSPICE Start Up conditions

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From: Ingraham, Andrew (Andrew.Ingraham@compaq.com)
Date: Wed Mar 22 2000 - 12:42:52 PST


> I had a lot of problems getting a spice model of a gigabit ethernet chip
> to run properly.
...

Not knowing how this gigabit Ethernet chip works, my concern is over DC
biasing. I think you said the outputs of one chip are AC-coupled to the
transmission line, and the far end of the line has a terminating resistor
between the wires of the pair but not to ground or some other reference. So
what determines the common-mode DC level on the t-line?

Presumably there is some sort of biasing circuit inside the second chip, or
else HSPICE would have complained about no DC path to ground. I'd be
curious what this biasing circuit is.

Whenever SPICE starts up, it finds the initial state by effectively ignoring
all capacitors (treating them as open-circuits) and inductors (treating them
as shorts) and solving for DC. It doesn't precisely "charge up" the
capacitors the same way a real circuit would. You can force it to do that,
by initially setting ALL voltage sources to zero and then ramping them up as
if the power supplies were turning on. This would probably make for a very
long simulation, however, since it would need to span milliseconds or
seconds, rather than nanoseconds.

In certain cases, particularly if something in the circuit has multiple
stable states, SPICE could arrive at a different initial state than it would
if everything had to actually charge up like the real circuit does.

Also (and this might be the key to your problem), in a transient simulation,
SPICE assumes quiescent conditions at t=0, meaning all time-varying signals
are effectively turned off for all time prior to t=0. Then at t=0+, they
suddenly turn on. When signals are AC-coupled, this can indeed upset the
bias conditions. Does the real circuit ever operate with no signals for an
extended period of time (~seconds)? I bet it doesn't.

In SPICE, if the driver chip initially has one output high and the other
low, SPICE probably initially sets the output side of the coupling
capacitors to equal voltages, i.e., UNequal bias voltages across the two
caps. Over a VERY long time, perhaps measured in seconds, and with a ~50%
duty cycle signal, the two caps would re-bias to have equal voltages across
them. But in the meantime, the conditions would be offset. There is
nothing wrong with SPICE; it is just telling you what the real circuit would
do if you had no signals for a few hours, then turned them on.

One way around that, is to set the initial voltages on the two coupling
capacitors, as it appears you have done.

SPICE can't do this itself, because the initial bias point across those
capacitors is a function of the time-varying signals, which weren't running
for t<=0.

Your bias time-constant is roughly 5 usec. If you didn't set the initial
conditions correctly, you might need to run the simulation for several
time-constants (many thousands of bit periods) for the bias point to
correctly re-establish itself.

Andy

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