From: S. Weir (email@example.com)
Date: Mon Mar 20 2000 - 12:51:16 PST
As usual, I think you are correct, I believe I mistakenly placed two right
parens after -k1, when they belong on the outside after Fstim. I will have
to dig-out old papers to confirm, but I agree it looks wrong that the MTBF
would be first order for any of the terms k2, Fclk, or Fstim.
At 09:16 AM 3/20/2000 -0700, you wrote:
>"S. Weir" wrote:
> > Shayle,
> > The best that we can do is to reduce the probability that a metastable
> > condition will propagate. The generally accepted metastability equation is
> > based on observations conducted with a two stage shift register circuit.
> > MTBF_2stage = ( e^( -k1 )) / ( k2*Fclk*Fstim )
> > k1 = metastable resolution constant
> > k2 = metastable susceptability window
> > Fclk = sampling clock frequency
> > Fstim = Asynchronous input stimulus frequency
>This doesn't look right. The MTBF should be exponential with Fclk,
>D. C. Sessions
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