RE: [SI-LIST] : Fast edge termination choice

About this list Date view Thread view Subject view Author view

From: Peterson, James F (FL51) (james.f.peterson@honeywell.com)
Date: Sat Feb 26 2000 - 07:42:16 PST


Shayle-
Reduced, yes, but not for that reason : the voltage wouldn't be halved at
the load nor in the reflection (remember, in a series term', you'll have a
reflection coefficient of almost +1 at the load, so it will double).

Another interesting thing about series terminations is that the initial wave
injected on the t-line has the same rise time as the reflected wave which is
2x the initial wave, thus the edge-rate doubles in magnitude!

If the net is point to point and short, I always start out with what D.C.
suggested : no termination. That's the cheapest way and sometimes it works
(gotta simulate).

-jim

-----Original Message-----
From: Shayle Hirschman [mailto:shayle@mho.net]
Sent: Friday, February 25, 2000 11:49 AM
To: si-list@silab.eng.sun.com
Subject: RE: [SI-LIST] : Fast edge termination choice

That's interesting, Andy. Can I infer, then, that EMI or perhaps coupling
is reduced more by series source termination since the voltage and current
are halved near the source?

Shayle

At 05:19 PM 2/25/00 -0500, you wrote:
>>Does series source termination defeat the purpose of selecting the fast
>>slew rate option? Will it slow the edge transition time down, or will the
>>signal still transition and travel as fast as if there was no termination,
>>but simply be divided (thereby depending on the reflection at the
>>destination)?
>
>If you imagine driving ideal transmission lines, then there is no
difference
>on edge rates of the voltage at the far end of the line.
>
>But with a small capacitive load, series termination would slow the edge
>rate down a little.
>
>If the line length is small, you have an RC network with some time
constant.
>Adding series termination increases R. Adding parallel termination reduces
>R somewhat.
>
>For a long line, it's more complicated. But if you looked just at the load
>end and small time intervals compared to the line delay, your time constant
>at that node is Zo*C without parallel termination, Zo*C/2 with it.
>
>> Could it be that it
>>reduces EMI, not by slowing the edges down, but rather just simply because
>>it terminates? And that, therefore, as far as EMI goes, parallel
>>termination would have a similar EMI result?
>
>Either termination can help, but there is more to it than just that.
>
>Series termination reduces the size of both the voltage steps (delta-V) and
>current steps (delta-I) of each pulse. The signal driven into the line is
>approximately a half-sized replica of what it would have been even with
>parallel termination. dv/dt and di/dt are about half. At the end of the
>line, the voltage doubles, so the magnitude (and dv/dt) there are the same
>as they would be for parallel termination, except for capacitive loading
>effects noted above. di/dt at the load end is nearly zero for series
>termination.
>
>Regards,
>Andy
>
>
>
>**** To unsubscribe from si-list or si-list-digest: send e-mail to
majordomo@silab.eng.sun.com. In the BODY of message put: UNSUBSCRIBE
si-list or UNSUBSCRIBE si-list-digest, for more help, put HELP.
>si-list archives are accessible at http://www.qsl.net/wb6tpu
>****
>
>

**** To unsubscribe from si-list or si-list-digest: send e-mail to
majordomo@silab.eng.sun.com. In the BODY of message put: UNSUBSCRIBE si-list
or UNSUBSCRIBE si-list-digest, for more help, put HELP.
si-list archives are accessible at http://www.qsl.net/wb6tpu
****

**** To unsubscribe from si-list or si-list-digest: send e-mail to majordomo@silab.eng.sun.com. In the BODY of message put: UNSUBSCRIBE si-list or UNSUBSCRIBE si-list-digest, for more help, put HELP.
si-list archives are accessible at http://www.qsl.net/wb6tpu
****


About this list Date view Thread view Subject view Author view

This archive was generated by hypermail 2b29 : Thu Apr 20 2000 - 11:35:11 PDT