Not really. The output current doesn't go instantaneously from full-drive
sink (or off) to full-drive source, so the output waveform isn't *entirely*
a capacitive-charging curve. In fact (as we've been discussing) real loads
are close to the real axis, so the I/T curve dominates.
> Why don't the IC manufacturers defne the output driver broadly in line with the above?
Actually, that's what too many do and what we've been griping about.
-- D. C. Sessions firstname.lastname@example.org
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