When the v/2 incident wave doubles at the open circuit, that event is for
all practical purposes part of the "incident wave", although it does require
the open circuit to occur.
Incidentally (npi) the rise time of that part of the waveform between v/2
and v (I guess) would be the same as the incident wave (otherwise the new
spectral components of energy would appear from nowhere).
This must double the rise time of the full voltage signal at the end,
compared to the original, although I've never checked this with an
**** To unsubscribe from si-list: send e-mail to email@example.com. In the BODY of message put: UNSUBSCRIBE si-list, for more help, put HELP. si-list archives are accessible at http://www.qsl.net/wb6tpu/si-list ****