RE: [SI-LIST] : Nyquist Sampling Rate

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From: Thomas Jackson (tjackson@fmi.fujitsu.com)
Date: Fri Mar 30 2001 - 17:07:51 PST


Adam,

The sampling theorem assumes that you are sampling a band-limited signal.
Therefore, the highest possible frequency signal through any two points
would be a sinewave at 1/2 the sampling rate. Anything else would have
frequency components above the Nyquist rate and that violates the first
assumption.

By the way, it should be obvious that the two samples cannot occur at the
zero crossings.

Tom

Thomas L. Jackson, P.E.
Staff VLSI Design Engineer
Network Access Development
Systems Solutions Group
FUJITSU MICROELECTRONICS, INC.
3545 North First Street
San Jose, CA  95134-1804
telephone: (408) 922-9574
facsimile: (408) 922-9618
http://www.fujitsumicro.com

-----Original Message-----
From: AA [mailto:alokbya@yahoo.com]
Sent: Friday, March 30, 2001 4:43 PM
To: si-list@silab.eng.sun.com
Subject: [SI-LIST] : Nyquest Sampling Rate

DEAR SI list subscribers,
Can any one explain to me how you can recover a
periodic signal form only 2 samples. I can understand
the math but I am having difficulty visualizing this.
Draw me any 2 points in the time domain and I can make
endless number of periodic signal go through them?

I know I am missing a key point but I can quite put my
finger on it.

Your input is very well appreciated.

Adam

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